Jawaban PTS SCHOOLOGY beserta soal dan pembahasannya
Nama: Alfina Grinadina Kelas: X MIPA 2 Absen: 6 1. Jika vektor a = (1 2 3), b = (5 4 –1), c = (4 –1 1) maka vektor a + 2b – 3c a + 2b - 3c = (1,2,3) + 2(5,4,-1) - 3(4,-1,1) = (1,2,3) + (10,8,-2) - (12,-3,3) = (1+10-12 , 2+8-(-3) , 3+(-2)-3) = (-1,13,-2) Jadi, (-1,13,-2) (D) 2. Diketahui |a| = √3, |b| = 1, dan |a - b| = 1, |a + b| = |a - b|² = a² - 2ab + b² 1² = √3² - 2ab + 1² 1 = 3 - 2ab + 1 2ab = 3 + 1 - 1 2ab = 3 ab = 3/2 |a + b|² = a² + 2ab + b² |a + b|² = √3² + 2.(3/2) + 1² |a + b|² = 3 + 3 + 1 |a + b|² = 7 |a + b| = √7 Jadi, nilai dari |a + b| = √7 (C) 3. ...